METRONMETHOD. REASON. LEARN.
Energy · 12 min

Kinetic energy

The square of speed explains why doubling speed makes much more energy available in a collision or braking process.

01Why this matters

The square of speed explains why doubling speed makes much more energy available in a collision or braking process.

02See it

mass 2 kgspeed 3 m/sspeed² = 9Ek = 9 J
Read left to right: mass 2 kg → speed 3 m/s → speed² = 9 → Ek = 9 J. Each panel connects one part of the example.

03Understand it

Kinetic energy is energy associated with motion. For ordinary speeds, translational kinetic energy is ½mv².

Mass is measured in kilograms and speed in metres per second. Square the speed, multiply by mass, then halve. Kinetic energy is non-negative and is a scalar. It depends on the reference frame: a passenger at rest relative to a train is moving relative to the track.

04Guided example

Find the kinetic energy of a 2 kg trolley moving at 3 m/s.

  1. Square the speed: 3² = 9 m²/s².
  2. Multiply by the mass: 2 × 9 = 18.
  3. Halve the result: Ek = ½ × 18 = 9 J.

05Try it

Mass 4 kg, speed 2 m/s. Kinetic energy?
A little hint

Square speed before multiplying.

06Practise it

Mass 2 kg, speed 5 m/s. Kinetic energy?
A little hint

Use half mass times speed squared.

By what factor does kinetic energy rise if speed doubles?
A little hint

Compare (2v)² with v².

07Use it in the real world

At twice the speed, the same object has four times the kinetic energy. Under the same constant braking force, this means four times the braking distance in the idealised model.

Go a little deeper

Net work equals the change in kinetic energy. Rotating objects also have rotational kinetic energy, which this translational formula does not include.

08Quick check

Mass 3 kg, speed zero. Kinetic energy?
A little hint

The squared speed is zero.

09Summary

Kinetic energy is energy associated with motion. For ordinary speeds, translational kinetic energy is ½mv². Halve the result: Ek = ½ × 18 = 9 J.

Before moving on, explain the worked example in your own words. Use the hint on any question you want to revisit.

10Key idea

Ek = ½mv²

Ek: kinetic energy in J; m: mass in kg; v: speed in m/s.

v = √(2Ek/m), for m > 0

Find this in the formula library →