METRONMETHOD. REASON. LEARN.
Heat · 12 min

Temperature and specific heat

A large pot of water needs more energy than a small cup for the same temperature rise. Temperature change alone does not determine the energy needed.

01Why this matters

A large pot of water needs more energy than a small cup for the same temperature rise. Temperature change alone does not determine the energy needed.

02See it

0.5 kg waterrise 10 °Cc = 4,200Q = 21,000 J
Read left to right: 0.5 kg water → rise 10 °C → c = 4,200 → Q = 21,000 J. Each panel connects one part of the example.

03Understand it

Temperature describes thermal state. Specific heat capacity is the energy required to raise one kilogram of a substance by one kelvin.

For a substance with approximately constant specific heat and no phase change, Q = mcΔT. Mass is in kilograms and specific heat in J/(kg·K). A temperature difference of 1 °C equals a difference of 1 K. This does not mean the absolute Celsius and kelvin temperature readings are equal.

04Guided example

Heat 0.5 kg of water by 10 °C, using c = 4,200 J/(kg·K), with no losses.

  1. Identify m = 0.5 kg and ΔT = 10 K.
  2. Multiply mass and specific heat: 0.5 × 4,200 = 2,100 J/K.
  3. Multiply by temperature rise: Q = 2,100 × 10 = 21,000 J.

05Try it

Mass 1 kg, c = 4,200 J/(kg·K), rise 2 °C. Energy?
A little hint

Multiply mass, specific heat and change.

06Practise it

Temperature rises from 20 °C to 35 °C. Change?
A little hint

Subtract initial from final.

Mass 2 kg, c = 500 J/(kg·K), rise 3 K. Energy?
A little hint

Use Q = mcΔT.

07Use it in the real world

A heater must supply more than the ideal calculated energy if the container and surroundings also warm up. Heating time estimates need both power and an efficiency assumption.

Go a little deeper

During a phase change at constant pressure, energy can change the state without changing temperature. The relevant model then uses latent heat rather than mcΔT.

08Quick check

Q = 1,000 J, mass 1 kg, c = 500 J/(kg·K). Rise?
A little hint

Divide Q by mc.

09Summary

Temperature describes thermal state. Specific heat capacity is the energy required to raise one kilogram of a substance by one kelvin. Multiply by temperature rise: Q = 2,100 × 10 = 21,000 J.

Before moving on, explain the worked example in your own words. Use the hint on any question you want to revisit.

10Key idea

Q = mcΔT

Q: energy in J; m: kg; c: J/(kg·K); ΔT: temperature change in K or °C.

ΔT = Q/(mc), for m and c > 0

Find this in the formula library →